Wooden Playgrounds
Wooden Playgrounds
Metal Or Wood Playground Equipment For Your Child
What better surprise for a child than a fantastic playground in your own backyard. There are few things children love more than slides, swing sets, and playgrounds in general. Instead of making the trek to your neighborhood park, installing a playground in your own backyard is a great solution. There is a spectacular selection of quality playground equipment on the market, but the main choice you will have to make is between the actual materials. There many reasons why to make a backyard playground, but evaluate the differences between metal and wooden sets carefully before your purchase.
Regardless if you choose a piece of wooden or metal playground equipment, be sure that it follows all the proper safety standards. Also, keep in mind that children each year are injured by improperly playing on playground equipment without appropriate supervision. Even though this playground is in your own backyard instead of at the neighborhood park, your children should still play under adult supervision.
Years ago, most playground equipment was made from metal. Even today, most swing sets are still made from metal tubes attached to which is a chain. Metal equipment, although still available, has been far surpassed by wooden equipment. The main reason for the rise in popularity of wooden playground equipment is the customizations options. Also, many individuals choose wooden playground equipment since it can be built for less money than the purchase of a metal play set.
If you are the handy type looking to build your own fantastic outdoor playground creation, then wood is the best way to go. There are numerous kits that allow you to combine different types of slides, swings, climbing walls, and a variety of other aspects to customize the set. The planning and construction process required in creating wooden playground equipment is a great project for the entire family. Involve your children and allow them to express themselves in creating a custom set. Let your imagine roam wild!
Picking up a hammer and nails not sounding so attractive? Look to pre-made sets instead. Although you will not be able to customize the equipment, there are many fantastic options available in both metal and wood. Keep in mind that metal equipment should be regularly inspected to avoid and prevent rusting. If necessary, apply a rust-preventative paint or topcoat. Also, wooden playground equipment should also be evaluated for potential splits or splinters. Just like metal equipment, those made out of wood should have the proper weather coatings to keep the wood looking fresh.
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Please help me with this problem – I will vote “best answer” for best explanation & correct answer. Thanks.
In a playground, a wooden horse is attached to the ground by a stiff spring. When a 24-kg child sits on the horse, the spring compressed by 28 cm. With the child sitting on the horse, the spring oscillates up and down with a frequency of 0.88 Hz. What is the oscillation frequency of the spring when no one is sitting on the horse?
Guys, there is an answer. I’m sure variables cross out somehow so they’re not needed… I just can’t figure out how to do it.
The Answer is 2.5 Hz. <<--- If you get that, explain please 
...so far nobody got it yet.
Let M be the joint mass of child and wooden horse. Let m be the mass of the horse. The spring is compressed even if nobody is sitting on the horse, because the spring is supporting the weight of the horse. Fortunately, Hooke’s law is a linear relationship. As a result, the spring constant can be determined even if we don’t know this initial compression.
k = ∆F/∆x = 24 × 9.8 / 0.28 = 840 N/m.
Now, in SHM, ω² = k/m gives the angular frequency in terms of spring constant and mass. In the present case, when the child sits on the horse, mass is actually M, the sum of the mass of the child plus the mass of the wooden horse. Both oscillate together as a single body. ω equals 2πf, where f = 0.88 Hz. Thus, ω² = (2πf)² = 30.5721 rad/s. Solving for M,
M = k/ω² = 840/30.5721 = 27.476 kg.
m can now be determined as m = M − 24 = 3.476 kg.
This mass-spring combination has an oscillating frequency given by f = 1/2π √(k/m) = 1/2π √(840/3.476) = 2.474 Hz.
